Q. The number of unpaired electrons in tetrahedral $ [Ni(CO)_{4}] $ is
Delhi UMET/DPMTDelhi UMET/DPMT 2010
Solution:
In $\left[N i(C O)_{4}\right]$,
$Ni$ is present as $Ni$ atom.
$N i=[A r] 3 d^{8} 4 s^{2}$
$CO$, being a strong field ligand,
transfers the $4s$-electrons into $3d$-orbitals.
$\left[N i(C O)_{4}\right]=[A r]$
Thus, $\left[N i(C O)_{4}\right]$
does not contain any unpaired electron.
