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Q.
The number of unpaired electrons in $\left[NiCl_{4}\right]^{2-}, Ni\left(CO\right)_{4}$ and $\left[Cu\left(NH_{3}\right)_{4}\right]^{2+}$ respectively are :
Configuration for metal $(M)$ in various complex.
$Ni ^{2+}$ has $2$ unpaired electrons
$Ni ^{0}$ has zero unpaired electrons with $s p^{3}$-hybridisation.
$Cu ^{2+}$ has one unpaired electron with $d s p^{2}$-hybridisation.
$\therefore (b) $ is the correct answer, i.e.
Number of unpaired electron $(2,0,1)$