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Q. The number of unpaired electrons in $d^{6},$ low spin, octahedral complex is

Coordination Compounds

Solution:

Low spin complex $\Rightarrow \Delta_{0}>P$

Thus pairing takes place in $t_{2 g}$

$d^{6} \Rightarrow t_{2 g}^{6} e_{g}^{0}$

Thus unpaired electrons $=0$