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Q. The number of turns of primary and secondary coils of transformer are $500$ and $5000$ respectively. The voltage and frequency of primary coil are $800\, V$ and $50\, Hz$ respectively, then the frequency and voltage of secondary coil will be

Rajasthan PETRajasthan PET 2002

Solution:

$ \frac{{{V}_{S}}}{{{V}_{P}}}=\frac{{{N}_{S}}}{{{N}_{P}}} $
$ \Rightarrow $
$ {{V}_{S}}=\frac{{{N}_{S}}}{{{N}_{p}}}\times {{V}_{p}} $
$ =\frac{500}{500}\times 800 $
$ =8000V $ No change in the frequency of transformer.