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Q. The number of tetrahedral and octahedral void per unit cell of cubic closed packed structure is

J & K CETJ & K CET 2015The Solid State

Solution:

In ccp or fee structure Number of lattice points
$(Z)=4$
$\because$ Number of octahedral voids = Number of lattice points
$\therefore $ Number of octahedral voids $=4$
and Number of tetrahedral voids $=2 \times$
Number of octahedral voids
$\therefore $ number of tetrahedral voids $=2 \times 4=8$