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Q.
The number of structural and configurationalm isomers of a bromo compound, $C_5H_9Br$, formed by the addition of HBr to 2-pentyne respectively are
Haloalkanes and Haloarenes
Solution:
Addition of $HBr$ of $2$-pentyne gives two structural isomers (I) and (II) $CH_3 - C \equiv C- CH_2CH_3 \xrightarrow{HBr} \underset{\text{(I)}}{CH_3C(Br) = CHCH_2CH_3} + \underset{\text{(II)}}{CH_3CH = C(Br)CH_2CH_3}$Each one of these will exist as a pair of geometrical isomers. Thus, there are two structural and four configurational isomers.