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Q.
The number of square faces that are present in a truncated octahedron is ........
The Solid State
Solution:
The truncated octahedron is the$14-$faced Archimedean solid, with $14$ total faces: $6$ squares and $8$ regular hexagons.
The truncated octahedron is formed by removing the six right square pyramids one from each point of a regular octahedron as:
Truncated octahedron unfolded in two-dimension.
