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Chemistry
The number of sp2 hybrid orbitals in a molecule of benzene is
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Q. The number of $sp^{2}$ hybrid orbitals in a molecule of benzene is
NTA Abhyas
NTA Abhyas 2020
A
18
100%
B
6
0%
C
12
0%
D
24
0%
Solution:
Benzene: $C_{6}H_{6}$
As in Benzene, Each carbon is $sp^{2}$ Hybridized
Total number of carbon $=6\left(\right.sp^{2}$ Hybridized)
In one $sp^{2}$ hybrid. number of orbitals = 3
Hence total Hybrid orbitals $=6\times 3=18$