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Q.
The number of solutions of the equation $\sin^{- 1}x=\left(\sin x\right)^{- 1}$ is/are
NTA AbhyasNTA Abhyas 2022
Solution:
$\because \left(\sin x\right)^{- 1}=\frac{1}{\sin x}=\text{cosec} x$
Now, from graphs of $\sin^{- 1} x , \text{cosec} x$
Clearly, both graph intersects at two points
$\therefore $ two solutions