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Q. The number of six digit numbers that can be formed from the digits $1, 2, 3,4, 5, 6,7$ so that digits do not repeat and the terminal digits are even, is

Permutations and Combinations

Solution:

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$ 1^{st}$ place can be filled in $3$ ways and 6th place in $2$ ways and rest of the places in $5 \times 4 \times 3 \times 2$ ways.
$\therefore $ Required numbers $= 3 \times 2 \times 5\times 4 \times 3 \times 2 = 720$.