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Physics
The number of revolutions done by an electron in one second in the first orbit of a hydrogen atom is
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Q. The number of revolutions done by an electron in one second in the first orbit of a hydrogen atom is
NTA Abhyas
NTA Abhyas 2020
Atoms
A
$6.57\times 10^{15}$
43%
B
$6.57\times 10^{13}$
28%
C
$6.57\times 10^{11}$
15%
D
$6.57\times 10^{14}$
14%
Solution:
$\mathrm{v}_1(\mathrm{t})=\mathrm{n} \cdot\left(2 \pi \mathrm{r}_1\right)$
We know that $frequency=\frac{v e l o c i t y}{d i s t a n c e}$
$\frac{v_{1}}{2 \pi r_{1}}=\frac{2.18 \times 10^{6}}{2 \pi \times 0.529 \times 10^{- 10}}$
$=6.57\times 10^{15}$