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Q. The number of possible enantiomeric pairs that can be produced during monochlorination of $2$-methylbutane is

Haloalkanes and Haloarenes

Solution:

First draw possible different structures obtained on monochlorination of $2$-methylbutane, $CH _{3} CH \left( CH _{3}\right) CH _{2} CH _{3} .$
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Thus structures (i) and (iii) are optically active, each has one chiral carbon; so each structure will give one enantiomeric pair; thus total enantiomeric pairs will be two.