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Q. The number of points at which the function $f\left(x\right)=\left|x - 0 .5\right|+\left|x - 1\right|+tanx$ is not differentiable in the interval $\left(0 , 2\right)$ is/are

NTA AbhyasNTA Abhyas 2022

Solution:

The curve will have sharp corner at $x=0.5$ and at $x=1$ and a point of discontinuity at $x=\frac{\pi }{2}$ .
Hence, total number of points where the function is not differentiable is $3$ .