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  4. The number of neutrons in 1.8 g of water will approximately be

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Q. The number of neutrons in 1.8 g of water will approximately be

Some Basic Concepts of Chemistry

Solution:

$H_{2}O=2_{1}^{1}H+^{16}_{8}O$
$\therefore $ neutrons $^{1}_{0}n=0+8$
$^{n}H_{2}O=\frac{1.8}{18}=0.1$
Hence $^{1}_{0}n=8\times0.1\times6.02\times10^{23}$
$=4.816\times10^{23}$