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Q.
The number of moles of oxygen in $1 \,L $ of air containing $21\%$ oxygen by volume, under standard conditions, is
AIPMTAIPMT 1995Some Basic Concepts of Chemistry
Solution:
Volume of oxygen in $1 \,L$ of air
$\frac{21}{100} \times 1000=210 \,mL$
$\therefore 22400\, mL$ volume at STP is occupied by oxygen $=1$ mole
Therefore, number of moles occupied by $210\, mL$
$\frac{210}{22400}$
$=0.0093\, mol$