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  4. The number of moles of KMnO4 that will be needed to react with one mole of sulphite ion in acidic solution is

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Q. The number of moles of $KMnO_4$ that will be needed to react with one mole of sulphite ion in acidic solution is

AIPMTAIPMT 2007Organic Chemistry – Some Basic Principles and Techniques

Solution:

$2KMnO_4 + 3H_2SO_4 \rightarrow K_2 SO_4 + 2MnSO_4$
$ +3H_2O + 5 [O]$
$[MnO^{-}_4 + 8H^+ + 5e^-\rightarrow Mn^{2+} + 4H_2O] \times 2$
$\frac {[SO_3^{2-} + H_2O \rightarrow SO_4^{2-} + 2H^+ + 2e^-] \times 5} {2MnO_4^{-} + 6H^+ + 5SO_3^{2-} \rightarrow 2Mn^{2+} + 5 SO _4^{2-} + 3H_2O}$
$5$ moles of sulphite ions react with
= $2$ moles of $MnO_4^-$
So, $1$ mole of sulphite ions react with
$ = \frac {2}{5} \, moles \, of \, MnO_4^{-} $.