1. Tardigrade
  2. Question
  3. Chemistry
  4. The number of moles of KMnO4 required to oxidise one equivalent of KI in the presence of sulphuric acid is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The number of moles of $KMnO_4$ required to oxidise one equivalent of $KI$ in the presence of sulphuric acid is

KVPYKVPY 2014

Solution:

$\overset{+7}{KMnO_{4}}+\overset{-1}{KI}+H_{2}SO_{4}\rightarrow$
$\overset{+2}{Mn}SO_{4}+\overset{0}{I}_{2}+K_{2}SO_{4}+H_{2}O$
Balance factor for $Mn = 5$
Balance factor for $I=1$
Equivalent of $KMnO_4$ = equivalent of $KI$
Number of equivalents = $y \times$ Number of moles
where, $y$ is the balance factor.
$=y_{Mn}\times n_{Mn}=y_{KI}\times n_{KI} $
$=5\times x_{Mn}=1\times1$
$n_{Mn}=\frac{1}{5}$