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  4. The number of moles of KMnO4 reduced by one mole of KI in alkaline medium is

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Q. The number of moles of $ KMnO_{4}$ reduced by one mole of $KI$ in alkaline medium is

ManipalManipal 2009The d-and f-Block Elements

Solution:

$2 KMnO _{4}+ H _{2} O + KI \longrightarrow 2 MnO _{2} +2 KOH + KIO _{3}$
Hence, one mole of KI reduces two moles of $KMnO _{4}.$