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Q. The number of moles of $KMnO_4$ reduced by one mole of $KI$ in alkaline medium is

Some Basic Concepts of Chemistry

Solution:

$\overset{+7}{KMnO_4} \xrightarrow{OH^-} \overset{+6}{K_2MnO_4}$
Change in oxidation number of $Mn$ in basic medium is $1$.
Hence, mole of $KI$ is equal to mole of $KMnO_4$.