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  4. The number of moles of electron required to reduce 0.2 mole of Cr 2 O -27 to Cr +3

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Q. The number of moles of electron required to reduce $0.2$ mole of $Cr _2 O ^{-2}_7$ to $Cr ^{+3}$

KCETKCET 2019Redox Reactions

Solution:

$Cr_{2}^{+6}O_{7}^{2-} \rightarrow [6e^{-}] 2 Cr^{+3}$
$1$ mol requires 6 mole of electrons
$0.2$ mol requires $\frac{0.2\times6}{1}=1.2 \,$ mol of electrons