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  4. The number of molecules of water in 333 g of Al 2( SO 4)3 ⋅ 18 H 2 O is

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Q. The number of molecules of water in $333 \,g$ of $Al _{2}\left( SO _{4}\right)_{3} \cdot 18 H _{2} O$ is

Some Basic Concepts of Chemistry

Solution:

Formula of the compound suggests that one molecule of the compound contains $18$ molecules of water. Number of water molecules in $333 \,g$ of compound

=number of moles $\times 6.023 \times 10^{23} \times 18 $

$=\frac{333}{666} \times 6.023 \times 10^{23} \times 18=9 \times 6.023 \times 10^{23}$