Question

The number of molecules of $ C{{O}_{2}} $ present in 44 g of $ C{{O}_{2}} $ is:

• A. $ 6.0\times {{10}^{23}} $
• B. $ 3\times {{10}^{23}} $
• C. $ 12\times {{10}^{23}} $
• D. $ 3\times {{10}^{10}} $

Answer 1

Answer: (A)

Key Idea : 1 mole $=$ molecular mass in gram
$=6.02 \times 10^{23}$ molecules
Given ulass Uf $CO _{2}=44 \,g$
Molecular mass of $CO _{2}=12+16 \times 2=44$
$\therefore $ No. of molecules in $44 \,g$
of $CO _{2}=6.02 \times 10^{23}$