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  4. The number of ions given by [Pt(NH3)6]Cl4 in aqueous solution will be

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Q. The number of ions given by $[Pt(NH_{3})_{6}]Cl_{4}$ in aqueous solution will be

Coordination Compounds

Solution:

$\left[Pt\left(NH_{3}\right)_{6} \right]Cl_{4} {\rightleftharpoons} \left[Pt\left(NH_{3}\right)_{6}\right]^{4+}+4Cl^{-}$
Total number of ions given in aqueous solution = $5$