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Q. The number of iodine atoms present in $1cm^{3}$ of its 0.1 M solution is

NTA AbhyasNTA Abhyas 2020Some Basic Concepts of Chemistry

Solution:

$\text{1000} \, \text{cm}^{\text{3}} \, \text{of} \, \text{0} \text{.1} \, \text{M} \, \text{solution} \equiv \text{0} \text{.1} \, \text{mol} \, \text{I}_{\text{2}}$

So $1 \, \text{cm}^{\text{3}} \, \text{of} \, \text{solution} \, \equiv \, 0.1 \times 10^{- 3} \, \text{mol} \, \text{I}_{\text{2}}$

Hence $\text{1} \, \text{mol} \, \text{I}_{\text{2}}$ contains $= 6.02 \times 10^{23} \, \text{I}_{\text{2}}$ molecules

So $0.1 \times 10^{- 3} \, \text{mol} \, \text{I}_{\text{2}}$ contains

$= 6.02 \times 10^{23} \times 0.1 \times 10^{- 3} \, \text{I}_{\text{2}}$ molecules

$= 12.04 \times 10^{19} \, \text{I}_{\text{2}}$ atoms.