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  4. The number of gram molecules of oxygen in 6.02 × 1024 CO molecules is

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Q. The number of gram molecules of oxygen in $6.02 \times 10^{24} \,CO$ molecules is

AIPMTAIPMT 1990Some Basic Concepts of Chemistry

Solution:

$6.023 \times 10^{23}$ molecules of $CO =1$ mole of $CO$
$6.02 \times 10^{24}$ molecules of $CO =10$ moles of $CO$
$=10\, g$ atoms of $O$
$=5 \,g$ molecules of $O _{2}$