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Q.
The number of gram equivalent of $H _{2} SO _{4}$ in $1000 \,mL \,3\, M$ solution, is:
Jharkhand CECEJharkhand CECE 2003
Solution:
$H _{2} SO _{4} \rightarrow 2 H ^{+}+ SO _{4}^{2-} $
$\because 1$ mole $H _{2} SO _{4}=2 \,g-$ equivalent of $H _{2} SO _{4} $
$\therefore 3$ mole $H _{2} SO _{4}=2 \times 3\, g -$ equivalent of $H _{2} SO _{4}$
$=6\, g -$ equivalent of $H _{2} SO _{4}$