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Q. The number of geometric isomers that can exist for square planar $\left(\left[P t \left(C l\right) \left(p y\right) \left(N H_{3}\right) \left(N H_{2} O H\right)\right]\right)^{+}$ is (py = pyridine):

NTA AbhyasNTA Abhyas 2022

Solution:

Complex with general formula [Mabcd]+ square planar complex can have three isomers.
Solution