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Q. The number of ether isomers possible for $C_{4}H_{10}O$ are:

ManipalManipal 2006

Solution:

$\underset{\text{Diethyl ether}}{C _{2} H _{5} OC _{2} H _{5}}$
$\underset{\text{Methyl n-propyl ether}}{CH _{3} O \cdot CH _{2} CH _{2} CH _{3}}$
$\underset{\text{Methyl isopropyl ether}}{CH _{3}- O - CH \left( CH _{3}\right)_{2}}$