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  4. The number of electrons involved in the reduction of one nitrate ion to hydrazine is

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Q. The number of electrons involved in the reduction of one nitrate ion to hydrazine is

Redox Reactions

Solution:

Oxidation state of $N$ in $NO^{-}_{3}$ is $+5$ Oxidation state of $N$ in $N_{2}H_{4}$ is $-2$ So number of electrons involved in the reduction of one nitrate ion to hydrazine is $6$