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Q.
The number of electrons involved in the conversion of $MnO_4^-$, to $MnO_2$ is
Redox Reactions
Solution:
$MnO_4^- \to MnO_2$
Oxidation number of
$MnO_{4}^{-} : x - 8 = -1 \Rightarrow x = +7$
Oxidation number of
$MnO_{2} : x - 4 = 0 \Rightarrow x = +4$
Change in oxidation number $= 3$