1. Tardigrade
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  3. Chemistry
  4. The number of electrons in [ 19 K 40]-1 is

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Q. The number of electrons in $\left[{ }_{19} K ^{40}\right]^{-1}$ is

AIIMSAIIMS 1994Structure of Atom

Solution:

Atomic No. $=19$

$e ^{-}$ present originally $=19$

total no. of $e ^{-}$ $=19+1$ (from $- ve$

$=20 \,\,\,\,\,$ charge $)$