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Q. The number of different permutations, each containing all letters of the word "STATESMAN" is

Permutations and Combinations

Solution:

"STATESMAN"
Total number of letters = 9,
Number of S's = 2, Number of T's = 2, Number of A's = 2
$\therefore $ Required number of permutations
$ = \frac{9!}{(2)! (2)!(2)!} = 45360$