Thank you for reporting, we will resolve it shortly
Q.
The number of different permutations, each containing all letters of the word "STATESMAN" is
Permutations and Combinations
Solution:
"STATESMAN"
Total number of letters = 9,
Number of S's = 2, Number of T's = 2, Number of A's = 2
$\therefore $ Required number of permutations
$ = \frac{9!}{(2)! (2)!(2)!} = 45360$