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Q. The number of diagonals in a hexagon is

KEAMKEAM 2017Permutations and Combinations

Solution:

The number of diagonals in a $n$ -side polygon
$=\frac{n(n-3)}{2}$
$\therefore $ Number of diagonals in a hexagon
$=\frac{6(6-3)}{2} $
$=9$