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  4. The number of coulombs required to reduce 12.3 g of nitrobenzene to aniline, is

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Q. The number of coulombs required to reduce 12.3 g of nitrobenzene to aniline, is

CMC MedicalCMC Medical 2014

Solution:

$ {{C}_{6}}{{H}_{5}}N{{O}_{2}}+6{{H}^{+}}+6{{e}^{-}}\xrightarrow{{}}{{C}_{6}}{{H}_{5}}N{{H}_{2}}+2{{H}_{2}}O $ 1 mol (= 123 g) nitrobenzene requires 6 moles of electrons = 6 x 96500 C charge $ \therefore $ 12.3g nitrobenzene will require charge $ =\frac{6\times 96500\times 12.3}{123} $ $ =6\times 9650=57900\,C $