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Chemistry
The number of atoms in 4.25 g of NH3 is approximately
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Q. The number of atoms in $4.25 \,g $ of $NH_3$ is approximately
AIPMT
AIPMT 1999
Some Basic Concepts of Chemistry
A
$6.023 \times 10^{23}$
19%
B
$4 \times 6.023 \times 10^{23}$
19%
C
$1.7 \times 10^{24}$
13%
D
$4.5 \times 6.023 \times 10^{23}$
49%
Solution:
Molar mass $=14+3=17$
No.of moles $=\frac{4.25}{17}=0.25$ moles
1 mole $=4 \times 6.022 \times 10^{27}$ atoms
$0.25 mole =.25 \times 4 \times 6.022 \times 10^{23}=6.022 \times 10^{23}$ atoms