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  4. The nuclei 613 C and 714 N can be described as

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Q. The nuclei ${ }_{6}^{13} C$ and ${ }_{7}^{14} N$ can be described as

Nuclei

Solution:

Number of neutrons for carbon $=13-6=7$
Number of neutrons for nitrogen $=14-7=7$
Both the nuclei have equal number of neutrons.
Hence, they are isotones.