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Q.
The normal reaction on a body placed in a lift moving up with constant acceleration $2ms^{- 2}$ is $120N$ . Mass of the body is (Take $g=10 \, ms^{- 2}$ )
NTA AbhyasNTA Abhyas 2022
Solution:
From force diagram shown in figure,
$N-mg=ma_{0}$
or $120-mg=2m$
$\therefore m=\frac{120}{g + 2}=\frac{120}{10 + 2}$
$=10$ kg
