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Chemistry
The non existence of PbI4 and PbBr4 is due to
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Q. The non existence of $PbI_4$ and $PbBr_4$ is due to
COMEDK
COMEDK 2014
Redox Reactions
A
highly oxidizing nature of $Pb^{4+}$ ions
16%
B
highly reducing nature of $I^-$ and $Br^-$ ions
14%
C
larger size of $Pb^{4+}, Br^-$ and $I^-$ ions
9%
D
both $(a)$ and $(b)$.
62%
Solution:
The non-existence of $PbI_4$ and $PbBr_4$ is probably due to the strong oxidizing power of $Pb^{4+}$ ions and strong reducing power of $I^-$ and $Br^-$ ions.