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Q. The network shown in figure is part of a complete circuit. If at a certain instant, the current $I$ is $5A$ and decreasing at a rate $10^{3}As^{- 1}$ then $V_{B}-V_{A}$ is:
Question

NTA AbhyasNTA Abhyas 2020

Solution:

Solution
From $KVL$ $A$ to $B$
$V_{A}-\left(\right.1\times 5\left.\right)+15+\left(5 \times \left(10\right)^{- 3}\right)\left(10\right)^{3}=V_{B}$
$V_{B}-V_{A}=+15volt$