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  4. The nearer point of hypermetropic eye is 40 cm. The lens to be used for its correction should have the power

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Q. The nearer point of hypermetropic eye is $40 \,cm$. The lens to be used for its correction should have the power

Chhattisgarh PMTChhattisgarh PMT 2010

Solution:

Hypermetropia can be removed by using a convex lens Focal length of used lens
$ f=+d=+40\, m $ = + (defected near point)
$ \therefore $ Power of lens $ =\frac{100}{f(cm)}$
$=\frac{100}{40} =2.5\,D $