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Q.
The nature of $s-t$ graph shown here is a parabola. From this graph we find that
Motion in a Straight Line
Solution:
$ s=u t+\frac{1}{2} a t^{2} ;$
When $u=0, s=\frac{1}{2} a t^{2}$
i.e., $s-t$ graph is a parabola symmetric about $s$ -axis.
Further, $s=\frac{1}{2} a t^{2}$ implies $\frac{d^{2} s}{d t^{2}}$ is independent of $t,$ i.e., the body is moving with uniform acceleration. So option (c) is correct.