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Q. The n rows each containing $m$ cells in series are joined in parallel. Maximum current is taken from this combination across an external resistance of $30$ resistance. If the total number of cells used are $24$ and internal resistance of each cell is $ 0.5\,Q $ then

J & K CETJ & K CET 2005

Solution:

In mixed grouping the current in the external circuit will be maximum when the internal resistance of the battery is equal to the external resistance,
$R=\frac{m r}{n}$
Given, $R=3\, \Omega, r=0.5\, \Omega$
$\therefore 3=\frac{m}{n} \times 0.5$
$\Rightarrow \frac{m}{n}=6$
$\Rightarrow m=6 n$..(i)
Total number of cells $=m \times n=24 \ldots$ (ii)
From Eqs. (i) and (ii), we get
$6 n \times n=24$
$\Rightarrow 6 n^{2}=24$
$\Rightarrow n^{2}=4$
$\Rightarrow n=2, m=12$

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