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Q. The most stable oxidation state of lanthanides is

J & K CETJ & K CET 2013The d-and f-Block Elements

Solution:

The general electronic configuration of lanthanides is
$[X e](n-2) f^{1-14}(n-1) d^{1} n s^{2}$
$\because$ After the loss of both of the 65 electrons and also the solitary $d$ electrons, the lanthanoids gain stable configurations.
$\therefore +I I I(+3)$ oxidation state is most common among lanthanides.