Question

The most basic hydroxide from the following is

• A. $Pr\left(\right.OH\left(\left.\right)_{3}\left(\right.Z=59\left.\right)$
• B. $Sm\left(\right.OH\left(\left.\right)_{3}\left(\right.Z=62\left.\right)$
• C. $Ho\left(\right.OH\left(\left.\right)_{3}\left(\right.Z=67\left.\right)$
• D. $La\left(\right.OH\left(\left.\right)_{3}\left(\right.Z=57\left.\right)$

Answer 1

Answer: (D)

The basic nature of hydroxides decreases from La to Lu along the lanthanide series due to lanthanoid concentration. Thus, $La\left(\right.OH\left(\left.\right)_{3}$ is the most basic hydroxide.