Question

The moment of inertia of the pulley system as shown in the figure- $5.103$ is $4\, kgm ^{2}$. The radii of bigger and smaller pulleys $2\, m$ and $1 \,m$ respectively. The angular acceleration of the pulley system is: (take $g=10\, m / s ^{2}$ )

• A. $2.1 \,rad / s ^{2}$
• B. $4.2 \,rad / s ^{2}$
• C. $1.2\, rad / s ^{2}$
• D. $0.6\, rad / s ^{2}$

Answer 1

Answer: (A)

From figure shown

$50-T_{1}=5(2 \alpha)\,\,\,...(1)$
$T_{2}-40=4(\alpha)\,\,\,...(2)$
$T_{1}(2)-T_{2}(1)=4 \alpha\,\,\,...(3)$
From (1), (2) and (3)
$ 2(50-10 \alpha)-(40+4 \alpha) =4 \alpha$
$\Rightarrow 100-20 \alpha-40-4 \alpha =4 \alpha$
$\Rightarrow 28 \alpha =60 $
$\Rightarrow \alpha =\frac{60}{28}=2.1 \,m / s ^{2}$