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Q. The moment of inertia of a solid cylinder about an axis parallei to its length and passing through its. centre is equal to its moment of inertia about an axis perpendicular to the length of cylinder and passing through its centre. The ratio of radius of cylinder and its length is

Solution:

$\frac{MR^2}{2} = \frac{ML^2}{12} + \frac{MR^2}{4}$