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Q.
The moment of inertia of a rigid body in terms of its angular momentum $L$ and kinetic energy $K$ is
NTA AbhyasNTA Abhyas 2020System of Particles and Rotational Motion
Solution:
Angular momentum of a rigid body about a fixed axis is given by
$L=I\omega $
Where $I$ is moment of inertia and $\omega $ is angular velocity about that axis.
Kinetic energy of body is given by
$K=\frac{1}{2} \, I\omega ^{2}$
$\therefore $ $K=\frac{1}{2 I}\left(I \omega \right)^{2}=\frac{L^{2}}{2 I}$
$\Rightarrow $ $I=\frac{L^{2}}{2 K}$