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  4. The moment of inertia of a circular ring of mass 1 kg about an axis passing through its centre and perpendicular to its plane is 4 kg-m2 . The diameter of the ring is

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Q. The moment of inertia of a circular ring of mass $1\,kg $ about an axis passing through its centre and perpendicular to its plane is $4\, kg-m^{2}$ . The diameter of the ring is

J & K CETJ & K CET 2008System of Particles and Rotational Motion

Solution:

Moment of inertia of circular ring about an axis passing through its center of mass and perpendicular to its plane
$I=M R^{2}$
here $I=4\, k g-m^{2}$
$m =1\, kg$
$=R^{2}=\frac{4}{1}=4 R=2\, m$
Therefore, diameter of ring $=4\, m$