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  4. The moment of inertia of a circular loop of radius R, at a distance of R/2 around a rotating axis parallel to horizontal diameter of loop is

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Q. The moment of inertia of a circular loop of radius $R$, at a distance of $R/2$ around a rotating axis parallel to horizontal diameter of loop is

AIIMSAIIMS 2012

Solution:

According to theorem of parallel axis
$I=I_{ CM }+M\left(\frac{R}{2}\right)^{2}$
$I=\frac{1}{2} M R^{2}+\frac{M R^{2}}{4} $
$I=\frac{3}{4} M R^{2}$