Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The molecular weight of $NaCl$ , determined by studying freezing point depression of its $0.5\%$ aqueous solution is $30$ . The apparent degree of dissociation of $NaCl$ is:-

NTA AbhyasNTA Abhyas 2020

Solution:

$i=\frac{Theoretical molar wt}{Observed molar wt}=\frac{58 . 5}{30}=1.95$
$i=1-\alpha +nα$
$1.95=1-\alpha +2\alpha $
$\alpha =0.95$